Question

tìm x thuộc Z, biết

\(-4\frac{1}{3}.\left(\frac{1}{2}-\frac{1}{6}\right)< hoặc=x-\frac{2}{3}.\left(\frac{1}{3}-\frac{1}{2}-\frac{3}{4}\right)\)

ai nhanh mk sẽ tik cho. tối mai mk học rồi

Answer 1

\(\frac{-11}{9}\le x+\frac{11}{18}\Leftrightarrow x\ge\frac{-11}{6}\)

Answer 2

\(-4\frac{1}{3}.\left(\frac{1}{2}-\frac{1}{6}\right)\le x-\frac{2}{3}.\left(\frac{1}{3}-\frac{1}{2}-\frac{3}{4}\right)\)

\(\Rightarrow\frac{-13}{9}\le x-\frac{-11}{18}\)

\(\Leftrightarrow\frac{-13}{9}\le x+\frac{11}{18}\)

\(\Rightarrow x\ge\frac{-37}{18}\)

Học tốt nhé !! ^-^

Answer 3

cảm ơn Lâm Việt Phúc nhé