\(\left(x+\frac{3}{5}\right).\left(\frac{-4}{3}-x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x+\frac{3}{5}=0\\\frac{-4}{3}-x=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{-3}{5}\\x=\frac{-4}{3}\end{cases}}}\)
\(\left(x+\frac{3}{5}\right)\left(-\frac{4}{3}-x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{3}{5}=0\\-\frac{4}{3}-x=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-\frac{3}{5}\\x=-\frac{4}{3}\end{cases}}}\)
vậy \(x=-\frac{3}{5}\)hoặc \(x=-\frac{4}{3}\).
ta có : \(\left(x+\frac{3}{5}\right)\left(-\frac{4}{3}-x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x+\frac{3}{5}=0\\\frac{-4}{3}-x=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-\frac{3}{5}\\x=-\frac{4}{3}\end{cases}}\)
Ta có: \(\left(x+\frac{3}{5}\right).\left(-\frac{4}{3}-x\right)=0\)
=> \(x+\frac{3}{5}=0\)
\(x=0-\frac{3}{5}\)
\(x=-\frac{3}{5}\)
hoặc \(\frac{-4}{3}-x=0\)
\(x=-\frac{4}{3}-0\)
\(x=-\frac{4}{3}\)
Vậy x= \(-\frac{3}{5}\)
và x= \(-\frac{4}{3}\)