x(x - 1)(x - 1) = (x - 2)xx(x - 1)
<=> x(x - 1)x(x - 1) - (x - 2)xx(x - 1) = (x - 2)xx(x - 1) - (x - 2)xx(x - 1)
<=> x(x - 1)x(x - 1) - (x - 2)xx(x - 1) = 0
<=> x2(x - 1) = 0
<=> x = 0
<=> x - 1 = 0
x = 0 + 1
x = 1
=> x = 0 hoặc 1
tim cac gia tri x y thoa man
a,(x^2-1)(x^2-16)<0 va x thuoc Z
B,1/x-y/8=1/16 va x y thuoc N
Tim cac gia tri x, y thoa man:
a, ( x2 - 1 ) ( x2 - 16 ) < 0 ca x thuoc z
b, 1/x - y/8 = 1/16 va x, y thuoc N
c, | x+1 | + | x+2 | + | x+3 | = x
tim x,y thuoc N* biet 1+x+x^2+x^3=2^y
Tim x,y thuoc N*,biet: 1/x+1/y=1/2
tim x thuoc n
1/3+1/6+1/10+.....+2/x*(x+1)=4020/2011
Tim x thuoc N biet
( x - 2 ) ^2016 + ( x -3 ) = 1
tim x, y thuoc N de 1! + 2! + ... + x! = y!
tim x thuoc Z de A thuoc Z va tim gia tri do A=\(\frac{1-2x}{x+3}\)
