x . (x - 1 - 2 (x - 1))=0
x - 1 - 2 . (x - 1 )= 0 : x
x - 1 - 2 . ( x - 1 ) = 0
2.( x - 1) = 0 + 1 + x
2.( x - 1 ) = 1 + x
suy ra x = 3
tim x thuoc N
c) (x-1 ) ( x +3 ) =0 d) x ( x-1 =2 ( x-1) =0
tim x,y thuoc n khac 0 TM
1!+2!+...+x!=y^2
1/tim n thuoc N sao cho:
a/(2n+12) chia het cho (n+2)
b/(3n+5) chia het cho (n-2)
2/ tim x sao cho:
a/(x+3).(x^2+1)=0
b/(x+7).(x^2-36)=0
1) tim x thuoc n biet:
a) 3 mu 4 - x = 81
b) 5 mu x -1 = 125
c) (2 - x) mu 3=27 mu 0
d)3 mu x + 2 -3 mu x +1=182
e) 2 mu x -1 -2 mu x =16
Tim x thuoc Z
1/ x(x+3)=0
2/ (x-2)(5-x)=0
3/(x-1)(x2+1)=0
1 )Tim x, y thuoc Z
x + y = x.y
2) Tim x thuoc Z
(x + 1)+(x+3)+(x+5)+...+(x+99)=0(x-3)+(x-2)+(x-1)+...+10+11=11-12(x-5)+7(3-x)=530(x+2)-6(x-5)-24x=100Tim x, y thuoc Z biet : | x-2| + (x-y+1)^2 =0
tim x thuoc Z
(x-1)(x^2+1)=0
(x-2)(7-x)>0
(x^2-1)(49-x^2)=0
tim x thuoc Z biet :
(x-1)^2 =(x-3)^4
HELP ME:0!!
