Question

tìm x thuộc N, biết

3x+8chia hết cho x+1

Answer 1

\(3x+8⋮x+1\)

\(\Rightarrow3x+3+5⋮x+1\)

\(\Rightarrow5⋮x+1\)

\(\Rightarrow x+1\in\left(1;5\right)\)

\(\Rightarrow x\in\left(0;4\right)\)

Answer 2

Bài này tách là đc ạ

\(3x+8⋮x+1\)

\(\Rightarrow3x+5+3⋮x+1\)

\(\Rightarrow\left(3x+3\right)+5⋮x+1\)

\(\Rightarrow3\left(x+1\right)+5⋮x+1\)

Có  3 ( x+1 ) chia hết cho x+1 => 5 cũng chia hết cho x+1

\(\Rightarrow x+1\inƯ\left(5\right)=\left\{1;5\right\}\)

Nếu x +1 =5 \(\Rightarrow x=5-1=4\)

Nếu x+1 = 1\(\Rightarrow1-1=0\)

\(\Rightarrow x\in0;4\)