\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=5750\)
\(100x+\left(1+2+3+4+...+100\right)=5750\)
\(100x+5050=5750\)
\(100x=5750-5050\)
\(100x=700\)
\(x=700\div100\)
\(x=7\)
Vậy ...
( X + 1 ) + ( X + 2 ) + ( X + 3 ) + ... + ( X + 100 ) = 5750
100 X + ( 1 + 2 + 3 + ... + 100 ) = 5750
100 X + 5050 = 5750
100 X = 5750 - 5050
100 X = 700
X = 700 : 100
X = 7
Vậy x = 7
(x+1) + (x+2) + (x+3) + ..... + (x+100) = 5750
( x+x+x+...+x ) + ( 1 + 2 + 3 + ... + 100 ) = 5750
=> 100x + ( 1+2+3+...+100 ) = 5750
=> 100x + 5050 = 5750
100x = 5750 - 5050
100x = 700
x = 700 : 100
x = 7