Question

Tim x thuoc N biet 

( x - 2 ) ^2016 + ( x -3 ) = 3

Answer 1

Đặt \(A=\left(x-2\right)^{2016}+\left(x-3\right)\)

\(x-2< 2\) vì nếu \(x-2\ge2\)

\(\Rightarrow x-3\ge1\)

\(\left(x-2\right)^{2016}>3\)

\(\Rightarrow A=\left(x-2\right)^{2016}+\left(x-3\right)>3\) ( vô lý )

\(\Rightarrow x-2< 2\)

\(\Rightarrow x< 4\)

Với \(x=0\)

\(\Rightarrow A=\left(x-2\right)^{2016}+\left(x-3\right)=2^{2016}-3>3\)

Với \(x=1\)

\(\Rightarrow A=\left(x-2\right)^{2016}+\left(x-3\right)< 0< 3\)

Với \(x=2\)

\(\Rightarrow A=\left(x-2\right)^{2016}+\left(x-3\right)=0-1< 3\)

Với \(x=3\)

\(\Rightarrow A=\left(x-2\right)^{2016}+\left(x-3\right)=1+0< 3\)

Do đó không có \(x\in N\) thỏa mãn.