Ta có : \(\left(x-2\right)^{2016}\)dương
\(\Rightarrow x-3=0\Rightarrow x=3\)
Thay x ta thử :
\(\left(3-2\right)^{2016}+\left(3-3\right)=1+0=1\)thỏa đề
Vậy \(x=3\)
Tim x thuoc N biet
( x - 2 ) ^2016 + ( x -3 ) = 3
tim x,y thuoc N* biet 1+x+x^2+x^3=2^y
tim x, y thuoc N biet:
1! + 2! +3! +....+ x! = y2
1) Tim a, b thuoc Q biet: a-b=2(a+b)=a:b
2) Tim x thuoc Q sao cho: (x-1)(x+3)<0
Tim x,y thuoc N*,biet: 1/x+1/y=1/2
tim x thuoc Z biet x^3-x^2+x-1=0
tim x thuoc z biet
a,1/(1×2) + 1/(2×3) + ... + 2/(x(x+1)) = 2005/2010
3 duong cao cua 1 tam giiac co do dai bang 4,12,x biet x thuoc n tim x
