\(2\left(x-5\right)+10=20\)
\(2x-10+10=20\)
\(2x=20\)
\(x=10\)
\(\left(3x+1\right)-17=5\)
\(3x+1-17=5\)
\(3x-16=5\)
\(3x=21\)
\(x=\frac{21}{3}=7\)
\(\left(10x+120\right)-138=262\)
\(10x+120-138=262\)
\(10x-18=262\)
\(10x=280\)
\(x=28\)
\(4\left(x+1\right)-12=8\)
\(4x+4-12=8\)
\(4x-8=8\)
\(4x=16\)
\(x=4\)
2.(x-5)+10 = 20
2.(x-5) = 20 - 10
2.(x-5) = 10
x-5 = 10 : 2
x-5 = 5
x = 5 + 5
x = 10
(3x+1)-17 = 5
3x+1 = 5 + 17
3x+1 = 22
3x = 22 - 1
3x = 21
x = 21 : 3
x = 7
(10x+120)-138 = 262
10x+120 = 262 + 138
10x+120 = 400
10x = 400-120
10x = 280
x = 280 : 10
x = 28
4.(x+1)-12 = 8
4.(x+1) = 8 + 12
4.(x+1) = 20
x+1 = 20 : 4
x+1 = 5
x = 5 - 1
x = 4
\(2x+2\frac{1}{3}=\frac{1}{2}:\frac{3}{2}\)
\(2x+\frac{7}{3}=\frac{1}{3}\)
\(2x=\frac{1}{3}-\frac{7}{3}\)
\(2x=-2\)
x = (-2) : 2
x = -1
2.(x-5)+10=20
2.(x-5)=20-10
2.(x-5)=10
x-5=5
\(\Rightarrow\)x=10
(3x+1)-17=5
3x+1=22
3x=21
\(\Rightarrow\)x=7
(10x+120)-138=262
(10x+120)=400
10x=280
\(\Rightarrow\)x=28
4.(x+1-10)=8
x+1-10=2
x+1=12
\(\Rightarrow\)x=11
\(2x+2\frac{1}{3}=\frac{1}{2}:\frac{3}{2}\)
\(2x+\frac{7}{3}=\frac{1}{3}\)
\(2x=\frac{-6}{3}=-2\)
\(\Rightarrow x=-1\)
2.(x-5)+10=20
2.(x-5)=10
x-5=10:2
x-5=5
x=5+5
x=10
(3x+1)-17=5
3x+1=5+17
3x+1=22
3x=22-1=21
x=21:3
x=7
(10.x+120)-138=262
10.x+120=262+138
10.x+120=400
10.x=400-120
10.x=280
x=280:10
x=28
