Question

Tìm x nguyên

1/2-(1/3+1/4)<x<1/48-(1/16-1/6)

Ghi chi tiết ra giùm mình ạ

 

Answer 1

`1/2-(1/3+1/4)<x<1/48-(1/16-1/6)`

`<=> 1/2 - (3 + 4)/(3 xx 4) < x < 1/48 - (3/28 - 8/48)`

`<=> 1/2 - 7/12 < x < 1/48 - (-5/48)`

`<=> 6/12 - 7/12 < x < 6/48`

`<=> -1/12 < x < 1/8`

`=>x=0`

Answer 2

\(\dfrac{1}{2}-\left(\dfrac{4+3}{12}\right)< x< \dfrac{1}{48}-\left(\dfrac{3}{48}-\dfrac{8}{48}\right)\\ \dfrac{24}{48}-\dfrac{7}{12}< x< \dfrac{1}{48}-\left(-\dfrac{5}{48}\right)\\ \dfrac{24-7.4}{48}< x< \dfrac{6}{48}\\ \dfrac{-4}{48}< x< \dfrac{6}{48}\\ -4< x< 6\)

=> x = { -3 ; -2 ;-1 ;0;1;2;3;4;5}