Do |x + 1| > hoặc = 0; |3 + x| > hoặc = 0; |5 + x| > hoặc = 0
=> 4x > hoặc = 0
=> x > hoặc = 0
Khi x > hoặc = 0 thì |x + 1| + |3 + x| + |5 + x| = (x + 1) + (3 + x) +(5 + x)
=> (x + 1) + (3 + x) + (5 + x) = 4x
=> 3x + 9 = 4x
=> 4x - 3x = 9
=> x = 9
cho fx=12x-2/4x+1 tim cac gia tri nguyen x de fx nguyen
tim cac so nguyen x de cac bieu thuc sau co gia tri nguyen:
a.-24/x+18/x
b.2x-5/x+1
c.3x+2/x-1-x-5/x-1
d.5x-4/2x+3 - 2x-5/2x+3
tim x nguyen de \(\frac{2012\sqrt{x+5}}{1006\sqrt{x+1}}\)la so nguyen
A=x^2+3/x-2 tim GT nguyen cua x de A nhan GT nguyen
Tim cac gia tri nguyen cua x de cac gia tri bieu thuc sau la so nguyen
a, 9-2x/x-3
b,3x-5/x-2
c,-3/4-x
tim cac gia tri nguyen cua x de cac gia tri bieu thuc sau la so nguyen
a,9-2x/x-3
b,3x-5/x-2
c,-3/4-x
\(\frac{5}{\sqrt{2x+1+2}}\).Tim x de x la so nguyen
tim gia tri nguyên duong cua x và y sao cho 1/x+1/y=1/5
tìm so nguyen a de a^2+a+3/a+1
Cho 2 bieu thuc A=\(\frac{3x^2-9x+2}{x-3}\)va B=\(\frac{4x-7}{x-2}\). Tim cac gti cua x de ca 2 bieu thuc cung co gtri nguyen
