Các câu hỏi tương tự
Tìm x biết:
\(\left(\frac{-3}{4}\right)^{3x-1}=\frac{256}{81}\)
tìm x
\(\left(\frac{-3}{4}\right)^{3x-1}\) = \(\frac{256}{81}\)
Tìm x, biết :
a. \(3x^2-51=-24\)
b. \(5^x.\left(5^3\right)^2=625\)
c. \(\left(\frac{-3}{4}\right)^{3x-1}=\frac{256}{81}\)
Tìm x biết :
\(172x^2-7^9:98^3=2^{-3}\)
\(\left(\frac{-3}{4}\right)^{3x-1}=\frac{256}{81}\)
a)\(\left(\frac{12}{25}\right)^x\)\(\left(\frac{5}{3}\right)^{-2}\)\(\left(-\frac{3}{4}\right)^4\)
c)\(\left(-\frac{3}{4}\right)^{3x-1}\)=\(\frac{256}{81}\)
Tìm x:
a)\(5^x.\left(5^3\right)^2=625\)
b)\(\left(\frac{12}{25}\right)^x=\left(\frac{5}{3}\right)^{-2}-\left(-\frac{3}{5}\right)^4\)
c)\(\left(-\frac{3}{4}\right)^{3x-1}=\frac{256}{81}\)
d)\(172.x^2-7^9:98^3=2^{-3}\)
Tìm x, biêt:
a) \(\left(\frac{-3}{4}\right)^{3x-1}=\frac{256}{81}\)
b) \(172.x^2-7^9:98^3=2^{-3}\)
TÌm x
a)\(\left(\frac{-3}{4}\right)^{3x-1}=\frac{256}{81}\)
b) 172 . x2 - 79 : 98 3 = 2 -3
tìm x biết
a .\(\left(\frac{-3}{4}\right)^{3x-1}=\frac{256}{81}\)
b, \(172.x^2-7^9:98^3=2^{-3}\)
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