(6x - 11)3 = (-3)2 . 15 + 208
(6x - 11)3 = 9 . 15 + 208
(6x - 11)3 = 135 + 208
(6x - 11)3 = 343
(6x - 11)3 = 73 (cùng số mũ)
⇒6x - 11 = 7
6x = 7 + 11
6x = 18
x =3
Tìm số nguyên x biết :
\(\left(7x-11\right)^3=\left(-3\right)^2\cdot15+208\)
Tìm x
a) \(\left(\frac{-5}{3}\right)< x< \frac{-24}{35}.\left(\frac{-5}{6}\right)\)
b) \(\left(7x-11\right)^3=\left(-3\right)^2.15+208\)
1 ) \(\left(x-3\right).\left(x-5\right)< 0\)
2) \(-6x-\left(-7\right)=25\)
3) \(46-\left(x-11\right)=-48\)
4) \(\left(x+15\right).\left(x-2\right)=0\)
5) \(3.\left(4-x\right)-2.\left(x-5\right)=12\)
Làm ơn giúp mình nha cố gắng làm đúng nha !!!!
Tìm x :
a) \(3x\left(x-\frac{2}{5}\right)=0\)
b)\(\frac{2}{3}:x=2\frac{1}{2}:\left(-0,3\right)\)
c)\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)
d) \(\left|\frac{2}{3}.x-\frac{2}{3}\right|-\frac{2}{3}=\left|-\frac{2}{3}\right|\)
Tìm x:
\(\frac{\left(13\frac{2}{9}-15\frac{2}{3}\right)\cdot\left(30^2-5^4\right)}{\left(18\frac{3}{7}-17\frac{1}{4}\right)\cdot\left(25-12\cdot5^2\right)}\cdot x=\frac{\frac{2}{11}+\frac{3}{13}+\frac{4}{15}+\frac{5}{17}}{4\frac{1}{11}+\frac{5}{13}+\frac{9}{15}+\frac{13}{17}}\)
Bài 2 : Tìm x, biết :
\(a.\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)
\(b.\left(\frac{7}{12}+x\right)-\frac{11}{12}=\frac{2}{3}\)
tìm x
m) \(6x+x=5^{11}:5^9+3^1\)
n) \(7x-x=5^{21}:5^{19}+3\times2^2-7^0\)
o) \(7x-2x=6^{17}:6^{15}+44:11\)
p) \(3^x=9\)
q) \(4^x=64\)
u) \(\left|x-2\right|=0\)
v) \(\left|x-5\right|=7-\left(-3\right)\)
w) \(\left|x-5\right|=\left|-7\right|\)
t) \(2^x:2^5=1\)
r) \(9^{x-1}=9\)
x) \(\left|x\right|-5=3\)
y) \(15-2\left|x\right|=13\)
s) \(x^4=16\)
Tìm x biết:
a)\(\frac{2}{3}.\left(x-\frac{3}{8}\right)-x-\left(-\frac{7}{8}+\frac{2}{3}\right)=\left(\frac{-3}{4}\right)^3:1\frac{11}{16}\)
b)\(-\frac{7}{8}+\frac{7}{8}:\left(\frac{2}{3}-x\right)+\frac{5}{6}:\left(-1\frac{11}{35}\right)=\left(0,8\right)^2\)
Tìm x biết:
a, |3x+1|=15
b, (6x+12).(x-2)=0
c, 5.(x-3)+4=2(x+1)+7
d, \(\left(x-3\right)^{10}\)=\(\left(x-3\right)^7\)
