(1-2x)2=9
=>(1-2x)2=32=(-3)2
TH1: 1-2x=3
=>2x=1-3
=>2x=-2
=>x=-1
TH2: 1-2x=-3
=>2x=1-(-3)
=>2x=4
=>x=2
Vậy x\(\in\){-1;2}
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Tìm x:
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Tìm \(x:\)\(\left(2x-6\right)\left(x^2-1\right)-\left(3x-9\right)\left(x+1\right)^2=0\)
Bài 1 :Rút gọnleft(4x^2-3yright)a2y-left(3x^2-4yright)3y4x^2left(5x-3yright)-x^2left(4x+yright)2ax^2-aleft(1+2x^2right)-left{a-xleft(x+aright)right}Bài 2:Tìm xa)2xleft(x+1right)-x^2left(x+2right)+x^3-x+10b)4xleft(3x+2right)-6xleft(2x+5right)+21left(x-1right)0Bài 3:Rút gọnxleft(1+x+x^2+...+x^9right)-left(1+x+x^2+...+x^9right)
Đọc tiếp
Bài 1 :Rút gọn
\(\left(4x^2-3y\right)a2y-\left(3x^2-4y\right)3y\)
\(4x^2\left(5x-3y\right)-x^2\left(4x+y\right)\)
\(2ax^2-a\left(1+2x^2\right)-\left\{a-x\left(x+a\right)\right\}\)
Bài 2:Tìm x
a)\(2x\left(x+1\right)-x^2\left(x+2\right)+x^3-x+1=0\)
b)\(4x\left(3x+2\right)-6x\left(2x+5\right)+21\left(x-1\right)=0\)
Bài 3:Rút gọn
\(x\left(1+x+x^2+...+x^9\right)-\left(1+x+x^2+...+x^9\right)\)
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Tìm x ( Giúp với mình cần gấp )
Bài 1:Tìm x
a)\(\left(5x+1\right)^2=\frac{36}{49}\)
b)\(\left(x-\frac{2}{9}\right)^3=\left(\frac{2}{3}\right)^6\)
c)\(\left(8x-1\right)^{2x+1}=5^{2x+1}\)
Tìm x,y biết
a)\(|x-3\left|+2\right|y+\frac{1}{2}|\le0\)
b)\(\left|3x+4\right|=2\left|2x-9\right|\)
c)\(\left|15x-1\right|\ge31\)
d)\(\left|9-7x\right|=5x-3\)
e)\(\left|x+3\right|-2x=\left|x-4\right|\)
Tìm x :
\(\left|x-1\right|+\left|x-2\right|+\left|x-3\right|+\left|x-4\right|+\left|2x-5\right|=4\)
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Mình đag cần rất gấp. mọi ng giúp mình với
tìm x
|x+1|+|x-1|=2x-3
tìm x,y,z
\(\left|xy+\frac{2}{3}\right|+\left|yz-\frac{8}{9}\right|+\left|zx+\frac{3}{4}\right|=0\)
a) Tìm GTNN Của:
A=\(\left(2x+\dfrac{1}{3}\right)^4-1\)
a) Tìm GTLN Của:
B=\(-\left(\dfrac{4}{9}x-\dfrac{2}{15}\right)^6+3\)
Tìm nghiệm đa thức sau:
\(a.B\left(x\right)=\left(x+\frac{1}{2}\right).\left(x-3\right)\\ b.D\left(x\right)=x^2-x\\ c.E\left(x^3+8\right)\\ d.F\left(x\right)=2x-5+\left(x-17\right)\)
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\(h.G\left(x\right)=\left(3x-5\right)-\left(18-6x\right)\)