Question

Tìm x là số tự nhiên biết :

A)\(\frac{x}{17}\)= \(\frac{60}{204}\)

B) \(\frac{6+x}{33}\)= \(\frac{7}{11}\)

 

C)\(\frac{12+x}{43-x}\)= \(\frac{2}{3}\)

Answer 1

A)X=12 B)x=15

Answer 2

A/ \(\frac{x}{17}=\frac{60}{204}\)

\(204x=60.17\)

\(204x=1020\)

\(x=\frac{1020}{204}\)

\(x=\frac{17}{4}=4,25\)

vậy x= 4,25

B/ \(\left(6+x\right).11=33.7\)

\(66+11x=231\)

\(11x=231-66=165\)

\(x=\frac{165}{11}\)

\(x=15\)

vậy x = 15

C/ \(\left(12+x\right).3=\left(43-x\right).2\)

\(36+3x=86-2x\)

\(3x+2x=86-36\)

\(5x=50\)

\(x=\frac{50}{5}=10\)

vậy x=10

Answer 3

mk nhầm 

phần a là \(\frac{1020}{204}\)= 5 nha

mk nhầm, xin lỗi

Answer 4

a) \(\frac{x}{17}=\frac{60}{204}\)

\(\Rightarrow\frac{x}{17}=\frac{5}{17}\)

\(\Rightarrow x=5\)

Vậy x = 5

b) \(\frac{6+x}{33}=\frac{7}{11}\)

\(\Rightarrow\frac{6+x}{33}=\frac{21}{33}\)

\(\Rightarrow6+x=21\)

\(\Rightarrow x=21-6\)

\(\Rightarrow x=15\)

Vậy x = 15

c) \(\frac{12+x}{43-x}=\frac{2}{3}\)

\(\Rightarrow3\left(12+x\right)=2\left(43-x\right)\)

\(\Rightarrow36+3x=86-2x\)

\(\Rightarrow2x+3x=86-36\)

\(\Rightarrow5x=50\)

\(\Rightarrow x=50:5\)

\(\Rightarrow x=10\)

Vậy x  = 10

_Chúc bạn học tốt_