\(\sqrt{16.\left(1-2x\right)}\) -\(\sqrt{4.3}\) =\(\sqrt{3x}\) +\(\sqrt{9.\left(1-2x\right)}\)
(=)4\(\sqrt{1-2x}\) -2\(\sqrt{3x}\) =\(\sqrt{3x}\) +3\(\sqrt{1-2x}\)
(=)\(\sqrt{1-2x}\) -3\(\sqrt{3x}\) =0
(=)1-2x=3\(\sqrt{3x}\) (=)1-2x=9.3x(=)1-2x=27x(=)29x=1(=)x=\(\frac{1}{29}\)
Tìm x khi \(\sqrt{16-32x}-\sqrt{12x}=\sqrt{3x}+\sqrt{9-18x}\)
tìm x biết
\(\sqrt{16-32x}-\sqrt{12x}=\sqrt{3x}+\sqrt{9-18x}\)
tìm x:
\sqrt(8x-4)-2\sqrt(18x-9)+2\sqrt(32x-16)=12
a) 2\sqrt(32x + 16) - 3\sqrt(18x + 9) = \sqrt(8x + 4) - 6
giải các phương trình sau:
\(1,\sqrt{18x}-6\sqrt{\dfrac{2x}{9}}=3-\sqrt{\dfrac{x}{2}}\)
\(2,\sqrt{3x}-2\sqrt{12x}+\dfrac{1}{3}\sqrt{27x}=-4\)
3, \(3\sqrt{2x}+5\sqrt{8x}-20-\sqrt{18}=0\)
\(4,\sqrt{16x+16}-\sqrt{9x+9}=1\)
\(5,\sqrt{4\left(1-3x\right)}+\sqrt{9\left(1-3x\right)}=10\)
\(6,\dfrac{2}{3}\sqrt{x-3}+\dfrac{1}{6}\sqrt{x-3}-\sqrt{x-3}=\dfrac{-2}{3}\)
Rút gọn: (Giải chi tiết từng bước)
9) \(2\sqrt{8\sqrt{3}-2\sqrt{5\sqrt{3}}}-3\sqrt{20\sqrt{3}}\)
10) \(\sqrt{12x}-\sqrt{48x}-3\sqrt{3x}+27\) với x \(\ge\) 0
11) \(\sqrt{18x}-5\sqrt{8x}+7\sqrt{18x}+28\) với \(x\ge0\)
12) \(\sqrt{45a}-\sqrt{20a}+4\sqrt{45a}+\sqrt{a}\) với \(a\ge0\)
Cần gấp ạ
6) \(\sqrt{x^2+12x+36}=-x-6\)
7) \(\sqrt{9x^2-12x+4}=3x-2\)
8) \(\sqrt{16-24x+9x^2}=2x-10\)
9) \(\sqrt{x^2-6x+9}==2x-3\)
10) \(\sqrt{x^2-3x+\dfrac{9}{4}}=\dfrac{3}{x}x-4\)
\(3\sqrt{2x}-2\sqrt{18x}+\sqrt{32x}=2\)
\(3\sqrt{2x}-\sqrt{18x}+\dfrac{1}{2}\sqrt{32x}\)
