Question

Tìm x \(\in\)Z, biết:

a) \(\frac{1}{2}-\)\(\left(\frac{1}{3}+\frac{1}{4}\right)< x< \frac{1}{48}-\left(\frac{1}{16}-\frac{1}{6}\right)\)

b) \(4\frac{5}{9}:2\frac{5}{18}-7\le x< \frac{-2}{3}\cdot\left(\frac{1}{3}-\frac{1}{2}-\frac{3}{4}\right)\)

Answer 1

a)Ta có: 1/2-(1/3+1/4)= -1/12

           1/48-(1/16-1/6)=1/8

suy ra: -1/12<x<1/8

<=> -2/24<x<3/24

=>x thuộc:(-1/24 ;0 ;1/24 ;2/24 ;3/24)

Answer 2

x thuộc Z nhé các bạn

Answer 3

a)\(\frac{1}{2}-\left(\frac{1}{3}+\frac{1}{4}\right)< x< \frac{1}{48}-\left(\frac{1}{16}-\frac{1}{6}\right)\)

\(\Rightarrow\frac{1}{2}-\frac{7}{12}< x< \frac{1}{48}-\frac{-5}{48}\)

\(\Rightarrow\frac{-1}{12}< x< \frac{1}{8}\)

Mà \(x\in Z\Rightarrow x=0\)

b)\(4\frac{5}{9}:2\frac{5}{18}-7\le x< \frac{-2}{3}.\left(\frac{1}{3}-\frac{1}{2}-\frac{3}{4}\right)\)

\(\Rightarrow\frac{41}{9}:\frac{41}{18}-7\le x< \frac{-2}{3}.\frac{-11}{12}\)

\(\Rightarrow2-7\le x< \frac{11}{18}\)

\(\Rightarrow-5\le x< \frac{11}{18}\)

Mà \(x\in Z\Rightarrow x\in\){-5;-4;-3;-2;-1;0}

Chúc bạn học tốt