Question

tìm x \(\in\)Z biết: 2x + 5 = x – 1 + (x + 3) – (x – 3).

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Answer 1

2x + 5 = x – 1 + (x + 3) – (x – 3).

2x+5=x-1+x+3-x+3

2x+5=x+5

<=>2x+5-x-5=0

<=>x+0=0

<=>x=0

Vậy x=0

Answer 2

2x + 5 = x - 1 + (x + 3) - (x - 3)

<=> 2x + 5 = x - 1 + x + 3 - x + 3

<=> 2x - x - x + x = -5 -1 + 3 + 3

<=> x = 0

Vậy x = 0

Answer 3

Bài làm

2x + 5 = x - 1 + ( x + 3 ) - ( x - 3 )

2x + 5 = x - 1 + x + 3 - x + 3

2x - x - x + x = 3 + 3 - 1 - 5

x = 0

Vậy x = 0

Answer 4

2x+5=x-1+(x+3)-(x-3)

\(\Rightarrow2x+5=x-1+x+3-x+3\)

\(\Rightarrow2x+5=x+5\)

\(\Rightarrow2x-x=5-5\)

\(\Rightarrow x=0\)

Vậy x=0

Chúc bn học tốt

Answer 5

2x+5=x-1+(x+3)-(x-3)

<=> 2x+5=x-1+x+3-x+3

<=> 2x+5=x+5

<=> 2x+5-x-5=0

<=> 3x=0

<=> x=0

Vậy x=0

Answer 6

2x + 5 = x - 1 + ( x + 3 ) - ( x - 3 )

=> 2x + 5 = x - 1 + x + 3 - x + 3

=> 2x + 5 = x + 5

=> 2x + 5 -x - 5 = 0

=> 3x = 0

=> x = 0

Vậy x = 0