Question

tìm x hoặc y

(2x+1)(3y-2)=12

1+2+3+...+x = 50

Answer 1

(2x + 1).(3y - 2) = 12

Lập bảng:

2x + 1	-12	-6	-4	-3	-2	-1	1	2	3	4	6	12
x	-13/2	-7/2	-5/2	-2	-3/2	-1	0	1/2	1	3/2	5/2	11/2
3y - 2	-1	-2	-3	-4	-6	-12	12	6	4	3	2	1
y	1/3	0	-1/3	-2/3	-4/3	-10/3	14/3	8/3	2	5/3	4/3	1

Vậy...

\(1+2+3+...+x=50\Leftrightarrow\frac{\left(x+1\right).x}{2}=50\Leftrightarrow\left(x+1\right).x=100??\)

Answer 2

1,tự lập bảng rồi tìm

2,\(1+2+3+..+x=50\Leftrightarrow\frac{x\left(x+1\right)}{2}=50\Leftrightarrow x\left(x+1\right)=100\)

sai đề?

Answer 3

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