Question

Tìm x:   \(\frac{x+1}{2009}\)+\(\frac{x+5}{2005}\)+\(\frac{x+6}{2004}\)+\(\frac{x+10}{2000}\)=  -4

Answer 1

\(\frac{x+1}{2009}+\frac{x+5}{2005}+\frac{x+6}{2004}+\frac{x+10}{2000}=-4\)

<=>\(\frac{x+1}{2009}+1+\frac{x+5}{2005}+1+\frac{x+6}{2004}+1+\frac{x+10}{2000}+1=0\)

<=>\(\frac{x+2010}{2009}+\frac{x+2010}{2005}+\frac{x+2010}{2004}+\frac{x+2010}{2000}=0\)

<=>\(\left(x+2010\right)\left(\frac{1}{2009}+\frac{1}{2005}+\frac{1}{2004}+\frac{1}{2000}\right)=0\)

Do \(\frac{1}{2009}+\frac{1}{2005}+\frac{1}{2004}+\frac{1}{2000}\ne0\)

=>x+2010=0

<=>x=-2010

 

Answer 2

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