\(\frac{x-2}{4}=\frac{5+x}{3}\Rightarrow\frac{3\left(x-2\right)}{3.4}=\frac{4\left(5+x\right)}{3.4}\)
=>3(x-2)=4(5+x)
=>3.x-3.2=4.5+4.x
=>3.x-6=20+4.x
=>3.x-4.x=20+6
-x=26
x=-26
vậy x=-26
1) \(\frac{24}{-12}=\frac{x}{5}=\frac{-y}{3}\)Tìm x và y
2) \(\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-5}{25}\le\frac{x}{10}< \frac{-3}{4}+\frac{4}{14}+\frac{-2}{8}+\frac{-3}{5}+\frac{5}{7}\)Tìm x
3) \(\frac{8.x+18}{2.x+6}\)Tìm x
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
tìm x
\(\frac{4}{5}x-x-\frac{3}{2}x+\frac{4}{3}=\frac{1}{2}-\frac{6}{5}\)
tìm x
\(x-\frac{3}{4}-x\cdot\frac{2}{3}+x:\frac{1}{2}-x:\frac{2}{5}=\frac{11}{4}\)
\(\frac{x}{5}-\frac{2}{x-1}=\frac{2}{15}\)
Tìm x, biết:
\(a)\frac{x+1}{65}+\frac{x+2}{64}=\frac{x+3}{63}+\frac{x+4}{62}\)
\(b)\frac{x-5}{100}+\frac{x-4}{101}+\frac{x-3}{102}=\frac{x-100}{5}+\frac{x-101}{4}+\frac{x-102}{3}\)
Bài 1 : Tính :
B = \(\frac{\frac{1}{2}+\frac{3}{4}-\frac{5}{6}}{\frac{1}{4}+\frac{3}{8}-\frac{5}{12}}+\frac{\frac{3}{4}+\frac{3}{5}-\frac{3}{8}}{\frac{1}{4}+\frac{1}{5}-\frac{1}{8}}\)
Bài 2 : tìm x và y
a) x3 - 36x = 0
b) \(\frac{x-3}{y-2}=\frac{3}{2}\)và x - y = 4 ( x , y \(\in\)Z )
tìm x: \(\frac{1}{2}x+\frac{4}{5}.\left(2\frac{1}{2}+x\right)=3\frac{3}{4}\)
Tìm x, biết:
a. \(\frac{-2}{5}+\frac{6}{5}.\left(y-\frac{2}{3}\right)=\frac{-4}{15}\)
b.\(\frac{-2}{5}+\frac{2}{3}x+\frac{1}{6}x=\frac{-4}{15}\)
c. \(\frac{3}{2}x+\frac{-2}{5}-\frac{2}{3}x=\frac{-4}{15}\)
giúp dùm mình nhanh với nhé thnks các bạn nhiều
2.Tìm x
a) \(\frac{a}{b}x-\frac{7}{8}=\frac{1}{4}\)
b)\(\frac{3}{2}x-\frac{1}{2}=\frac{1}{3}:\left(\frac{-5}{6}\right)\)
c)\(\frac{2}{3}\left(x+\frac{5}{4}\right)-\frac{1}{3}\left(\frac{2}{3}-x\right)=\frac{4}{3}\)
