Câu hỏi của Doan Cuong

Question

tìm x: $\frac{1}{2}x+\frac{4}{5}.\left(2\frac{1}{2}+x\right)=3\frac{3}{4}$

Mới vô · Accepted Answer

$\frac{1}{2}x+\frac{4}{5}\cdot\left(2\frac{1}{2}+x\right)=3\frac{3}{4}$$\frac{1}{2}x+\frac{4}{5}\cdot\left(\frac{5}{2}+x\right)=\frac{15}{4}$$\frac{1}{2}x+\frac{4}{5}\cdot\frac{5}{2}+\frac{4}{5}\cdot x=\frac{15}{4}$$\frac{1}{2}x+2+\frac{4}{5}x=\frac{15}{4}$$\frac{1}{2}x+\frac{4}{5}x=\frac{15}{4}-2$$\frac{1}{2}x+\frac{4}{5}x=\frac{7}{4}$$x\left(\frac{1}{2}+\frac{4}{5}\right)=\frac{7}{4}$$x\cdot\frac{13}{10}=\frac{7}{4}$$x=\frac{7}{4}:\frac{13}{10}$$x=\frac{35}{26}$Câu trả lời: $\frac{1}{2}x+\frac{4}{5}\cdot\left(2\frac{1}{2}+x\right)=3\frac{3}{4}$$\frac{1}{2}x+\frac{4}{5}\cdot\left(\frac{5}{2}+x\right)=\frac{15}{4}$$\frac{1}{2}x+\frac{4}{5}\cdot\frac{5}{2}+\frac{4}{5}\cdot x=\frac{15}{4}$$\frac{1}{2}x+2+\frac{4}{5}x=\frac{15}{4}$$\frac{1}{2}x+\frac{4}{5}x=\frac{15}{4}-2$$\frac{1}{2}x+\frac{4}{5}x=\frac{7}{4}$$x\left(\frac{1}{2}+\frac{4}{5}\right)=\frac{7}{4}$$x\cdot\frac{13}{10}=\frac{7}{4}$$x=\frac{7}{4}:\frac{13}{10}$$x=\frac{35}{26}$

Mới vô · Answer

$\frac{1}{2}x+\frac{4}{5}\cdot\left(2\frac{1}{2}+x\right)=3\frac{3}{4}$$\frac{1}{2}x+\frac{4}{5}\cdot\left(\frac{5}{2}+x\right)=\frac{15}{4}$$\frac{1}{2}x+\frac{4}{5}\cdot\frac{5}{2}+\frac{4}{5}\cdot x=\frac{15}{4}$$\frac{1}{2}x+2+\frac{4}{5}x=\frac{15}{4}$$\frac{1}{2}x+\frac{4}{5}x=\frac{15}{4}-2$$\frac{1}{2}x+\frac{4}{5}x=\frac{7}{4}$$x\cdot\left(\frac{1}{2}+\frac{4}{5}\right)=\frac{7}{4}$$x\cdot\frac{13}{10}=\frac{7}{4}$$x=\frac{7}{4}-\frac{13}{10}$$x=\frac{9}{20}$Câu trả lời: $\frac{1}{2}x+\frac{4}{5}\cdot\left(2\frac{1}{2}+x\right)=3\frac{3}{4}$$\frac{1}{2}x+\frac{4}{5}\cdot\left(\frac{5}{2}+x\right)=\frac{15}{4}$$\frac{1}{2}x+\frac{4}{5}\cdot\frac{5}{2}+\frac{4}{5}\cdot x=\frac{15}{4}$$\frac{1}{2}x+2+\frac{4}{5}x=\frac{15}{4}$$\frac{1}{2}x+\frac{4}{5}x=\frac{15}{4}-2$$\frac{1}{2}x+\frac{4}{5}x=\frac{7}{4}$$x\cdot\left(\frac{1}{2}+\frac{4}{5}\right)=\frac{7}{4}$$x\cdot\frac{13}{10}=\frac{7}{4}$$x=\frac{7}{4}-\frac{13}{10}$$x=\frac{9}{20}$

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