\(\frac{1}{1.2}+\frac{1}{2.3}+....+\frac{1}{x\left(x+1\right)}=\frac{2009}{2010}\)
\(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-....-\frac{1}{x}+\frac{1}{x}-\frac{1}{\left(x+1\right)}=\frac{2009}{2010}\)
\(1-\frac{1}{x+1}=\frac{2009}{2010}\)
\(\frac{1}{x+1}=1-\frac{2009}{2010}=\frac{1}{2010}\)
\(\Leftrightarrow\) x + 1= 2010
< = > x = 2010 - 1 = 2009