Các câu hỏi tương tự
Tìm x:
1) \(\text{(x−1):0,16=−9:(1−x)}\)
2) \(\left(\left|x\right|-\dfrac{3}{2}\right)\left(2x^2-10\right)=0\)
3)\(8\sqrt{x}=x^2\left(x\ge0\right)\)
1. Tìm x:
a) \(\left(x-3\right).\left(x+2\right)< 0\)
b) \(\left(x+1\right).\left(x-2\right)\ge0\)
c) \(\left(x-1\right)^3-x^3+3x^2+6x-1=0\)
1. Tìm x:
a) \(\left(x-3\right).\left(x+2\right)< 0\)
b) \(\left(x+1\right).\left(x-2\right)\ge0\)
c) \(\left(x-1\right)^3-x^3+3x^2+6x-1=0\)
Tìm x, biết:
\(\left(x-\frac{1}{2}\right).\left(x+\frac{1}{2}\right)\ge0\)
Tìm x biết: \(\left|x.\left(x^2-\frac{5}{4}\right)\right|\ge0\)
\(\left(2x+3\right)^2+\left(3x-2\right)^4=0\) vì \(\left(2x+3\right)^2\ge0;\left(3x-2\right)^4\ge0\) nên\(\Rightarrow\hept{\begin{cases}\left(2x+3\right)^2=0\\\left(3x-2\right)^4=0\end{cases}\Rightarrow\hept{\begin{cases}2x+3=0\\3x-2=0\end{cases}}}\) \(\Rightarrow\hept{\begin{cases}x=-\frac{3}{2}\\x=\frac{2}{3}\end{cases}}\)
Tìm số nguyên x biết \(\left(x^2-\frac{4}{25}\right)\left(x^2-4\right)\left(x^2-\frac{16}{9}\right)\left(x^2-10\right)< 10\)
Tìm x∈Q biết: \(\left|x.\left(x^2-\frac{5}{4}\right)\right|\ge0\)
cho A=\(\frac{\sqrt{x}-3}{2}\left(x\ge0\right)\)Tìm x thuộc Z để A nguyên và <30