Question

tìm x bt:\(\frac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}\)\(.\frac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}\)\(=8^x\)

giúp mk nha! mơn nhiều!

Answer 1

Biểu thức trên tương đương với:

\(\frac{4^6}{3^6}.\frac{6^6}{2^6}=8^x\Leftrightarrow\frac{24^6}{6^6}=4^6=64^2=8^4\Leftrightarrow x=4\)

Answer 2

\(\frac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}.\frac{6^5+6^5+6^5+6^5+6^5}{2^5+2^5}=\frac{4^6}{3^6}.\frac{6^6}{2^6}=\frac{2^{12}.3^6.2^6}{3^6.2^6}=2^{12}\)

Answer 3

@PTAN@ 

tìm x mak sao ko tìm????