Tìm x , bt:
a, 75 : x = ( -5) + 20
75: x = 15
x= 75: 15
x= 5
Vậy x = 5
b, \(5^{x+5}\) - \(2017^0\) = \(2^3\) .3
\(5^{x+5}\) - 1 = 8 . 3
\(5^{x+5}\) - 1 = 24
\(5^{x+5}\) = 25
\(5^{x+5}\)= \(5^2\)
=> x + 5 = 2
=> x= 2-5
x= -3
Vậy x= -3
a, 75 : x = ( -5 ) + 20
75 : x = 15
x = 75 : 15
x = 5
b, \(5^{x+5}-2017^0=2^3.3\)
\(5^{x+5}-1=8.3\)
\(5^{x+5}-1=24\)
\(5^{x+5}=24+1\)
\(5^{x+5}=25\)
\(5^{x+5}=5^2\)
\(\Rightarrow x+5=2\)
\(x=2-5\)
\(x=-3\)
a.
75 : x = ( - 5 ) + 20
75 : x = 15
x = 75 : 15
x = 3
b.
5x+5 - 20170 = 23 x 3
5x+5 - 20170 = 8 x 3
5x+5 - 1 = 24
5x+5 = 24 + 1
5x+5 = 25
Mà 55 = 25 => x + 5 = 25
x = 25 - 5
x = 20
Vậy x = 20
Nhầm sửa phần b chỗ cuối
Mà 52 = 25 => x + 5 = 2
x = 2 - 5
x = -3
Vậy x = -3
\(75:x=-5+20\)
\(75:x=15\)
\(x=5\)
\(5^{x+5}-2017^0=2^3\cdot3\)
\(5^{x+5}-1=24\)
\(5^{x+5}=25\)
\(x+5=2\)
\(x=3\)