\(x+\frac{x}{3}+\frac{x}{2}+\frac{3}{4}=\frac{5}{3}\)
\(\Rightarrow x+\frac{x}{3}+\frac{x}{2}=\frac{5}{3}-\frac{3}{4}=\frac{11}{12}\)
\(\Rightarrow x\left(1+\frac{1}{3}+\frac{1}{2}\right)=\frac{11}{12}\)
\(\Rightarrow x.\frac{11}{6}=\frac{11}{12}\)
\(\Rightarrow x=\frac{11}{12}:\frac{11}{6}=\frac{11}{12}.\frac{6}{11}\)
\(\Rightarrow x=\frac{1}{2}\)
x + \(\frac{x}{3}\)+\(\frac{x}{2}\)+ \(\frac{3}{4}\)=\(\frac{5}{3}\)
x*1+ x*\(\frac{1}{3}\)+x*\(\frac{1}{2}\) = \(\frac{5}{3}-\frac{3}{4}\)
x *( 1+\(\frac{1}{3}\)+\(\frac{1}{2}\)) = \(\frac{11}{12}\)
x* \(\frac{11}{6}\) = \(\frac{11}{12}\)
x = \(\frac{11}{12}:\frac{11}{6}\)
x = \(\frac{1}{2}\)
Vậy \(x=\frac{1}{2}\)
