\(\frac{x+2}{3}=\frac{x-2}{2}\Rightarrow2\left(x+2\right)=3\left(x-2\right)\)
=>2x+4=3x-6
=>2x-3x=-4-6
=>-x=-10
=>x=10
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\(\frac{x+2}{3}=\frac{x-2}{2}\Rightarrow2\left(x+2\right)=3\left(x-2\right)\)
=>2x+4=3x-6
=>2x-3x=-4-6
=>-x=-10
=>x=10
Tim x biet:x(2+x^2)(7-x)=0
1,tim cac so nguyen x,y biet: -2/x=y/3 va x<0<y
2, Tim cac so nguyen x,y biet:x-3/y-2=3/2 va x-y=4
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