Question

tim x biet

(x+2)²+(x-3)²-2(x-1)(x+1)=9

su dung hang dang thuc nhe

Answer 1

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mik ko biết

mong bn thông cảm !$$%

Answer 2

\(\left(x+2\right)^2+\left(x-3\right)^2-2\left(x-1\right)\left(x+1\right)=9\)

<=> \(x^2+2x+4+x^2-6x+9-2\left(x^2-1\right)=9\)

<=> \(2x^2-4x+13-2x^2+2=9\)

<=> \(-4x+15-9=0\)

<=> \(-4x+6=0\)

<=> \(4x=6\)

<=> \(x=\frac{3}{2}\)