\(\left(x^2-5\right)\left(x+2\right)+5x=2x^2+17\)
\(\Leftrightarrow x^3-5x+2x^2-10+5x=2x^2+17\)
\(\Leftrightarrow x^3-10=17\)
\(\Leftrightarrow x^3=27\)
\(\Leftrightarrow x=\sqrt[3]{27}=3\)
=> x^3 -5x+2x^2-10+5x=2x^2+17
=>x^3+2x^2-5x+5x=2x^2+27
=>x^3=27
=>x=3
mình ko chắc lắm
(x2 - 5)(x + 2) + 5x = 2x2 + 17
x3 + 2x2 - 5x - 10 + 5x = 2x2 + 17
x3 + 2x2 - 10 = 2x2 + 17
x3 - 10 = 17
x3 = 17 + 10
x3 = 27
x3 = 33
x = 3