Các câu hỏi tương tự
|x+1/1.5|+|x+1/5.9|+...+|1/397.401|=101.x
tìm x biết; /x+1:(1.5)/+ /x+1: (5.9)/+........+ /x +1: (397.401)/=101x
\(\left|x+\frac{1}{1.5}\right|+\left|x+\frac{1}{5.9}\right|+...+\left|x+\frac{1}{397.401}\right|=101x\)
A ) / X + 2 / + / X + / + / X + frac{1}{2}/ 4X b ) / x + 1,1 / + / x + 1,2 / + / x + 1,3 / + / x + 1,4 / 5xc ) / x + frac{1}{1.3}/ + / x + frac{1}{3.5}/ + / x +frac{1}{5.7} / + ........ + / x + frac{1}{97.99}/ 50xd ) / x + frac{1}{1.5}/ + / x + frac{1}{5.9}/ + / x + frac{1}{9.13}/ + ......... + / x + frac{1}{397.401}/ 101x
Đọc tiếp
A ) / X + 2 / + / X + / + / X + \(\frac{1}{2}\)/ = 4X
b ) / x + 1,1 / + / x + 1,2 / + / x + 1,3 / + / x + 1,4 / = 5x
c ) / x + \(\frac{1}{1.3}\)/ + / x + \(\frac{1}{3.5}\)/ + / x +\(\frac{1}{5.7}\) / + ........ + / x + \(\frac{1}{97.99}\)/ = 50x
d ) / x + \(\frac{1}{1.5}\)/ + / x + \(\frac{1}{5.9}\)/ + / x + \(\frac{1}{9.13}\)/ + ......... + / x + \(\frac{1}{397.401}\)/ = 101x
Tìm x:
\(\frac{x}{1.5}+\frac{x}{5.9}+\frac{x}{9.13}+...+\frac{x}{53.57}=\frac{56}{57}\)
d, \(\frac{1}{1.5}+\frac{1}{5.9}+...........+\frac{1}{397.401}< \frac{1}{4}\)
Tìm x biết
a) \(\frac{x-1}{21}=\frac{3}{x+1}\)
b)\(\frac{7}{x}+\frac{4}{5.9}+\frac{4}{9.13}+...+\frac{4}{41.45}=\frac{29}{45}\)
tìm x
e)\(\frac{7}{x}+\frac{4}{5.9}+\frac{4}{9.13}+...+\frac{4}{41.45}=\frac{29}{45}\)
f)\(\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{8.9.10}\right)x=\frac{22}{45}\)
cho ham so y= f(x) =6/x
tinh f(1) ; f(1.5) ;f(2) ;f(3) ;f(-2/3)
tim x biet y=3 ; y=-2
tim y biet 1<x>3 ; 1.5 be hon hoac bang x lon hon hoac bang 6
diem nao trong cac diem sau day khong thuoc do thi ham s
A(-1;-6 ) ; B(-0.5 ;-12 ) ;C(-0.5 ; -13 ) ; D(-1/3 ; -3 )