\(\left|x-\frac{3}{5}\right|+2x-1=0\)
\(\Leftrightarrow2x-1=-\left|x-\frac{3}{5}\right|\)
\(\Leftrightarrow\orbr{\begin{cases}2x-1=-x-\frac{3}{5}\\2x-1=-\left(-x\right)-\frac{3}{5}\end{cases}\Leftrightarrow\orbr{\begin{cases}2x+x=\frac{-3}{5}+1\\2x-x=\frac{-3}{5}+1\end{cases}}\Leftrightarrow\orbr{\begin{cases}3x=\frac{2}{5}\\x=\frac{2}{5}\end{cases}}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{2}{15}\\x=\frac{2}{5}\end{cases}}\)
Vậy ..................
Chắc cách làm như thế :V
Tim xthuoc Z biet:
1,|2x-5|-|2x+9|=0
2,|x+1|-|x+2|-|3-x|=7
3,|2x+3|+|3x+2|-|4-x|=10
tim x biet :
( 2-x ) x (4/5-x ) < 0
(x - 3/2) x ( 2x + 1 ) > 0
tim cap so x,y nguyen biet :
a,\(|2x+3|+|2x-1|=\frac{8}{2|x-5|+2}\)
Tim x biet
(x+1/5)-4=-2
(2x+3)*(x-7)=0
31/9(x)-5/2=8/3
tim (x;y) biet (x+2y -3)^2016 + |2x + 3y - 5| =0
Tim x biet: \(\frac{x+2}{2x-1}=\frac{x-6}{2x+3}\)
tim x biet
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)
Tim x,y,z biet
2/x-1/+/2x+5/=\(\frac{14}{2+\left(3-2y\right)^{2020}}\)
Tim x biet
| 2x-1 | - | x-3 | = 0
