Ta có: \(\frac{x-3}{x+5}=\frac{5}{7}\)
\(\Rightarrow7.\left(x-3\right)=5.\left(x+5\right)\)
\(\Rightarrow7x-21=5x+25\)
\(\Rightarrow7x-5x=21+25=46\)
\(\Rightarrow2x=46\)
\(\Rightarrow x=46:2=23\)
Vậy x = 23
Ủng hộ mik nha!
Cho ham so y=y (x)=2x-0,3
Tinh f(1) f(-0;2)
Tim 2 so xy bietx/3=y/7va x+y=120 do
tim x biet :3/[x+2][x+5]+5[x+5][x+10]+7/[x+10][x+15]=x/[x+12][x+17]
|x-3|-|7-x|=5.tim x
Tim x,y,z biet:
(2|x|+5)/3=(3|y|-1)/5=(3-z)/7 va 2|x|+7|y|+3z=-14
tim x,y thuoc z biet x/5=y/3=z/4 và x-z=7
tim x,y thuộc z biết x/3=y/4=z/5 và 2z+3y+5z=86
Tim x biet
1/1*3+1/3*5+1/5*7+1/7*9+...+1/x(x+2)=16/34
6x-5/-7=5x-3/-5. Tim x
Tim x trong ti le thuc sau x-3/5-x=5/7 giup minh voi :)))))))
Tim x VA y (x-3).(y-5)=7
