\(\left(x-1\right)^2=\left(x-1\right)^4\)
\(\Rightarrow\left(x-1\right)^4-\left(x-1\right)^2=0\)
\(\Rightarrow\left(x-1\right)^2\left[\left(x-1\right)^2-1\right]=0\)
\(\Rightarrow\orbr{\begin{cases}\left(x-1\right)^2=0\\\left(x-1\right)^2-1=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x-1=0\\\left(x-1\right)^2=1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=1\\x-1=\orbr{\begin{cases}1\\-1\end{cases}}\end{cases}}\)Vậy x - 1=0 ; x-1=1;x-1=-1
=>x=1;x=2;x=0
Vậy \(x\in\left(0;1;2\right)\)
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