Question

Tìm x biết:

(x-1)/2004+(x+2)/2003-(x-3)/2002=(x-4)/2001

Answer 1

x+4/2000+1+x+3/2001+1=x+2/2002+1+x+1/2... y cho nay la cong voi 1/1 chu lkhong phai la cong 1 o duoi mau dau nhe) quy dong chuyen ve ta duoc: 
x+2004/2000+x+2004/2001-x+2004/2002-x+... 
(x+2004)(1/2000+1/2001-1/2002-1/2003)=... 
do 1/2000+1/2001-1/2002-1/2003 luon lon hon 0 nen suy ra: 
x+2004=0 suy ra x=-2004

Answer 2

x+4/2000+1+x+3/2001+1=x+2/2002+1+x+1/2... y cho nay la cong voi 1/1 chu lkhong phai la cong 1 o duoi mau dau nhe) quy dong chuyen ve ta duoc: 
x+2004/2000+x+2004/2001-x+2004/2002-x+... 
(x+2004)(1/2000+1/2001-1/2002-1/2003)=... 
do 1/2000+1/2001-1/2002-1/2003 luon lon hon 0 nen suy ra: 
x+2004=0 suy ra x=-2004

 

Answer 3

x+4/2000+1+x+3/2001+1=x+2/2002+1+x+1/2... y cho nay la cong voi 1/1 chu lkhong phai la cong 1 o duoi mau dau nhe) quy dong chuyen ve ta duoc: 
x+2004/2000+x+2004/2001-x+2004/2002-x+... 
(x+2004)(1/2000+1/2001-1/2002-1/2003)=... 
do 1/2000+1/2001-1/2002-1/2003 luon lon hon 0 nen suy ra: 
x+2004=0 suy ra x=-2004

 

Answer 4

 x+4/2000+x+3/2001=x+2/2002+x+1/2003 
cong 2 vao hai ve ta duoc 
x+4/2000+1+x+3/2001+1=x+2/2002+1+x+1/2... 
x+2004/2000+x+2004/2001-x+2004/2002-x+... 
(x+2004)(1/2000+1/2001-1/2002-1/2003)=... 
do 1/2000+1/2001-1/2002-1/2003 luon lon hon 0 nen suy ra: 
x+2004=0 suy ra x=-2004

Answer 5

x-1/2004+x-2/2003-x-3/2002=x-4/2001

{x-1/2004-1}+{x-2/2003}-{x-3/2002}-{x-4/2001}=0

{x-2005/2004}+{x-2005/2003}-{x-2005/2002}-{x-2005/2001}

x-2005(1/2004-1/2003+1/2002+1/2001)

vi (1/2004-1/2003+1/2002+1/2001) luon kha

Answer 6

\(\frac{x+4}{2000}+\frac{x+3}{2001}=\frac{x+2}{2002}+\frac{x+1}{2003}\)

=>\(\frac{x+4}{2000}+\frac{x+3}{2001}+2=\frac{x+2}{2002}+\frac{x+1}{2003}+2\)

=>\(\frac{x+2004}{2000}+\frac{x+2004}{2001}=\frac{x+2004}{2002}+\frac{x+2004}{2003}\)

=>\(\left(x+2004\right)\left(\frac{1}{2000}+\frac{1}{2001}+\frac{1}{2002}+\frac{1}{2003}\right)\)

mà \(\frac{1}{2000}+\frac{1}{2001}+\frac{1}{2002}+\frac{1}{2003}>0\)

=>\(x+2004=0\)

=>\(x=-2004\)