x đầu tiên = 100
x thứ hai = 1022
x thứ ba = 100
(x+60)-160=0
x+60=0+160
x+60=160
x=160-60=100
\(\left(x+60\right)-160=0\)
\(x+60=160-0\)
\(x+60=160\)
\(x=160-60=100\)
\(\left(x-425\right)+317=914\)
\(x-425=914-317\)
\(x-425=597\)
\(x=597+425=1022\)
\(\left(235-x\right)-81=54\)
\(235-x=54+81\)
\(235-x=135\)
\(x=235-135=100\)
(x-425)+317=0
x-425=-317
x=108
(235-x)-81=54
235-x=135
x=100
