\(\left(x-\frac{2}{9}\right)^3=\left(\frac{2}{3}\right)^6\)
\(\left(x-\frac{2}{9}\right)^3=\frac{64}{729}\)
\(\Rightarrow x-\frac{2}{9}=\frac{4}{9}\Leftrightarrow x=\frac{6}{9}=\frac{2}{3}\)
Chúc em học tốt!!!
\(\left(x-\frac{2}{9}\right)^3=\left(\frac{2}{3}\right)^6\)
\(\left(x-\frac{2}{9}\right)^3=\left(\left(\frac{2}{3}\right)^2\right)^3\)
\(\left(x-\frac{2}{9}\right)^3=\left(\frac{4}{9}\right)^3\)
\(\Rightarrow x-\frac{2}{9}=\frac{4}{9}\)
\(\Rightarrow x=\frac{4}{9}+\frac{2}{9}\)
\(\Rightarrow x=\frac{2}{3}\)
Vậy \(x=\frac{2}{3}\)
\(\left(x-\frac{2}{9}\right)^3=\left(\frac{2}{3}\right)^6\Leftrightarrow\left(x-\frac{2}{9}\right)^3=\left[\left(\frac{2}{3}\right)^2\right]^3\)
\(\Leftrightarrow\left(x-\frac{2}{9}\right)^3=\left(\frac{4}{9}\right)^3\Leftrightarrow x-\frac{2}{9}=\frac{4}{9}\)
\(\Leftrightarrow x=\frac{4}{9}+\frac{2}{9}\Leftrightarrow x=\frac{6}{9}=\frac{2}{3}\)
Vậy \(x=\frac{2}{3}\)
(x - 2/9)^3= 64/729
\(\Rightarrow\)(x-2/9)^3= (4/9)^3
\(\Rightarrow\)x-2/9= 4/9
\(\Rightarrow\)x= 4/9+2/9
\(\Rightarrow\)x= 6/9=2/3
VẬY X= 2/3
TL:
\(\left(x-\frac{2}{9}\right)^3=\left(\frac{4}{9}\right)^3\)
\(\Rightarrow x-\frac{2}{9}=\frac{4}{9}\)
\(\Rightarrow x=\frac{2}{3}\)
Vậy x=\(\frac{2}{3}\)
\(\left(x-\frac{2}{9}\right)^3=\left(\frac{2}{3}\right)^6\)
\(\Rightarrow\left(x-\frac{2}{9}\right)^3=\left[\left(\frac{2}{3}\right)^2\right]^3\)
\(\Rightarrow\left(x-\frac{2}{9}\right)^3=\left(\frac{4}{9}\right)^3\)
\(\Rightarrow x-\frac{2}{9}=\frac{4}{9}\)
\(\Rightarrow x=\frac{4}{9}+\frac{2}{9}\)
\(x=\frac{6}{9}=\frac{2}{3}\)
