Ta có \(\left(x-2\right)^7=\left(x-2\right)^{x+1}\)
\(\Rightarrow\left(x-2\right)^7-\left(x-2\right)^{x+1}=0\)
\(\Rightarrow\left(x-2\right)^1.\left[\left(x-2\right)^6-\left(x-2\right)^x\right]=0\)
\(\Rightarrow\left(x-2\right)^1=0\)hoặc \(\left(x-2\right)^6-\left(x-2\right)^x=0\)
Nếu \(\left(x-2\right)^1=0\Rightarrow x-2=0\Rightarrow x=2\)
Nếu \(\left(x-2\right)^6-\left(x-2\right)^x=0\Rightarrow\left(x-2\right)^6=\left(x-2\right)^x\Rightarrow x=6\)
Vậy...
ta có
\(\left(x-2\right)^7=\left(x-2\right)^{x+1}.\)
=>\(7=x+1\)
=>\(x=7-1\)
=>\(x=6\)
(X-2)^7 =(X-2)^X+1
=> 7=X+1
X=6
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