Question

tìm x biết

\(\left(\frac{4}{9}\right)^x=\left(\frac{8}{27}\right)^{10}\)

JUP MIK GẤP NHA MN

Answer 1

\(\left(\frac{4}{9}\right)^x=\left(\frac{8}{27}\right)^{10}\)

\(\Leftrightarrow\left(\frac{2}{3}\right)^{2x}=\left(\frac{2}{3}\right)^{30}\)

\(\Leftrightarrow2x=30\Leftrightarrow x=15\)

Answer 2

Bài làm

Ta có: \(\left(\frac{4}{9}\right)^x=\left(\frac{2}{3}\right)^{2x}\)

          \(\left(\frac{8}{27}\right)^{10}=\left(\frac{2}{3}\right)^{3.10}=\left(\frac{2}{3}\right)^{30}\)

\(\Rightarrow\left(\frac{2}{3}\right)^{2x}=\left(\frac{2}{3}\right)^{30}\)

\(\Rightarrow2x=30\)

\(\Rightarrow x=15\)

Vậy \(x=15\)

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