giúp mk vs các bạn ui
\(\left(\frac{1}{4}x-1\right)-\left(\frac{5}{6}x+2\right)-\left(1-\frac{5}{8}x\right)=3\)
=> \(\frac{1}{4}x-1-\frac{5}{6}x-2-1+\frac{5}{8}x=3\)
=> \(\left(\frac{1}{4}x-\frac{5}{6}x+\frac{5}{8}x\right)+\left(-1-2-1\right)=3\)
=> \(\frac{1}{24}x-4=3\)
=> \(\frac{1}{24}x=7\)
=> \(x=7:\frac{1}{24}=7\cdot24=168\)
Vậy x = 168
\(\left(\frac{1}{4}x-1\right)-\left(\frac{5}{6}x+2\right)-\left(1-\frac{5}{8}x\right)=3\)
\(\frac{1}{4}x-1-\frac{5}{6}x-2-1+\frac{5}{8}x=3\)
\(x\left(\frac{1}{4}-\frac{5}{6}+\frac{5}{8}\right)-\left(1+2+1\right)=3\)
\(x.\frac{1}{24}-4=3\)
\(x.\frac{1}{24}=7\)
\(x=7:\frac{1}{24}\)
\(x=168\)
Vậy \(x=168\).
\(\left(\frac{1}{4}x-1\right)-\left(\frac{5}{6}x+2\right)-\left(1-\frac{5}{8}x\right)=3\)
\(\Rightarrow\frac{1}{4}x-1-\frac{5}{6}x-2-1+\frac{5}{8}x=3\)
\(\Rightarrow\frac{1}{24}x-4=3\)
\(\Rightarrow\frac{1}{24}x=7\)
\(\Rightarrow x=168\)
thanks mấy bạn nha
