4 và 6 đều chẵn nên [2x-5]4 và [3y+1]6 đều \(\ge0\)
=> \(\left[2x-5\right]^4+\left[3y+1\right]^6\le0\)khi
\(\hept{\begin{cases}\left[2x-5\right]^4=0\\\left[3y+1\right]^6=0\end{cases}}\Rightarrow\hept{\begin{cases}2x-5=0\\3y+1=0\end{cases}}\Rightarrow\hept{\begin{cases}x=\frac{5}{2}\\y=-\frac{1}{3}\end{cases}}\)
Tìm x , y biết:
\(\left(2x-5\right)^{2016}+\left(3y+4\right)^{2020}\le0\)
Tìm x,y biết:\(\left(2x-\frac{1}{6}\right)^2+\left|3y+12\right|\le0\)
Tìm x,y biết \(\left(2x-5\right)^{2000}+\left(3y-4\right)^{2002}\le0\)
Tìm x, y biết:
\(\left(2x-5\right)^{2000}+\left(3y+4\right)^{2002}\le0\)
tìm x; y
\(\left(2x-5\right)^{2000}+\left(3y+4\right)^{2002}\le0\)
Tìm đa thức M biết rằng: \(M+\left(5x^2-2xy\right)=6x^2+9xy-y^2.\) .Tính giá trị của M khi x, y thõa mãn: \(\left(2x-5\right)^{2018}+\left(3y+4\right)^{2020}\le0\)
1.Tính
A= \(\frac{4^6.9^5+6^9.120}{-8^4.3^{12}-6^{11}}\)
B=\(1-\frac{1}{1-2^{-1}}+\frac{1}{1+\frac{1}{2^{-1}}}\)
2. Tìm x, biết:
a) \(\left(2x-3\right)^2=36\)
b) \(\left(2x-1\right)^5=243\)
c) \(\left(7x+2\right)^{-1}=3^{-2}\)
d) \(\left(2x-5\right)^{2000}+\left(3y+4\right)^{2002}\le0\)
tìm x,y biết:
a)\(\left(2x-5\right)^{2000}+\left(3y+4\right)^{2002}\le0\)
b)\(x=6:\frac{1}{3}-0,8:\frac{1,5}{\frac{3}{2}.0,4.\frac{50}{1:\frac{1}{2}}}+\frac{1}{4}+\frac{1+\frac{1}{2}.\frac{1}{0,25}}{6-\frac{46}{1+2,2.10}}\)
c)\(y=77^{-1}.7^4.11^2.\left(1.11\right)^4.\left(7^2\right)^{-8}.\left(7^{-8}\right)^{-3}.\frac{1}{\left(-11\right)^{-3}}\)
\(\left(2x-\frac{1}{6^{ }}\right)^2+\left|3y+12\right|\le0\)
