\(\frac{x+32}{11}+\frac{x+23}{12}=\frac{x+38}{13}+\frac{x+27}{14}\)
Tìm x
Cho \(\frac{x+32}{11}+\frac{x+23}{12}=\frac{x+38}{13}+\frac{x+27}{14}\). Tìm x.
Tìm x biết :
\(\frac{x+32}{11}\)+ \(\frac{x+23}{12}\)= \(\frac{x+38}{13}\)+ \(\frac{x+27}{14}\)
Tìm x biết
\(\frac{x+32}{11}+\frac{x+23}{12}=\frac{x+32}{13}+\frac{x+27}{14}\)
Tìm x
a) \(\frac{x+32}{11}+\frac{x+23}{12}=\frac{x+38}{13}+\frac{x+27}{14}\)
b) \(\frac{x+1}{3}=\frac{x-2}{4}\)
\(\frac{x+32}{11}\)+\(\frac{x+23}{12}\)=\(\frac{x+38}{13}\)+\(\frac{x+27}{14}\)
TÌM X, AI NHANH MÌNH SẼ TICK CHO!!!^-^
Tìm x biết
a) x+2x+3x+4x+...+100x=-213
b)\(\frac{1}{2}x-\frac{1}{3}=\frac{1}{4}x-\frac{1}{6}\)
c)3(x-2)+2(x-1)=10
d)\(\frac{x+1}{3}=\frac{x-2}{4}\)
e)\(\frac{x-6}{7}+\frac{x-7}{8}+\frac{x-8}{9}=\frac{x-9}{10}+\frac{x-10}{11}+\frac{x-11}{12}\)
f)\(\frac{x+32}{11}+\frac{x+23}{12}=\frac{x+38}{13}+\frac{x+27}{14}\)
Tìm x:
a) 3x.(x-1) +5.(2-x) = 3x2 - 7x + 6
b) (x + 2)2 = \(\frac{1}{2}-\frac{1}{3}\)
c) \(\frac{x+32}{11}\)+ \(\frac{x+23}{12}\)= \(\frac{x+38}{13}\)+ \(\frac{x+27}{14}\)
Tìm x Biết:
\(\frac{x+32}{11}+\frac{x+33}{12}=\frac{x+34}{13}+\frac{x+35}{14}\)