\(\frac{x+1}{1974}+1+\frac{x+2}{1973}+1+\frac{x+3}{1972}+1=-3+3\)
\(\Leftrightarrow\frac{x+1975}{1974}+\frac{x+1975}{1973}+\frac{x+1975}{1972}=0\)
\(\Leftrightarrow\left(x+1975\right)\left(\frac{1}{1974}+\frac{1}{1973}+\frac{1}{1972}\right)=0\)
=> x + 1975 = 0. => x = -1975 ( vì 1/1974 + 1/1973 + 1/1972 khác 0 )
Tìm x:
\(\frac{x+1}{1974}+\frac{x+2}{1973}+\frac{x+3}{1972}=-3\)
\(\frac{x+1}{1974}+\frac{x+2}{1973}+\frac{x+3}{1972}=-3\)
\(\frac{x+5}{2005}+\frac{x+6}{2004}+\frac{x+7}{2003}=-3\)
TÌM X
tim x biết (x+1) /1974 + (x+2) / 1973 + (x+3) / 1972=-3
Tìm x biết \(\frac{x+1}{1074}+\)\(\frac{x+2}{1974}\)\(+\frac{x+3}{1972}=3\)
Tim x biet: x+1/1974+x+2/1973+x+3/1972=-3
B1: Tìm x
a,\(\frac{2}{7}x\)-\(\frac{1}{3}x\) =\(\frac{5}{21}\)
b, \(\frac{x+1}{1974}\)+ \(\frac{x+2}{1973}\)+ \(\frac{x+3}{1972}\)= (-3)
B2: Tính
\(\frac{-9}{7}\)- \(\frac{5}{13}\)\(\frac{-39}{25}\)+ \(\frac{-1}{42}\)x \(\frac{-5}{6}\)
Mọi người giúp mình với ạ. Mình cảm ơn trước nhé ^_^
Tìm x thuộc Q, biết:
a) (x-4).(x+1/3)>0
b) x+1/1974 + x+2/1973 + x+3/1974 = -3
Tìm x biết
\(\frac{45-x}{1969}+\frac{40-x}{1974}+\frac{35-x}{1979}+\frac{30-x}{1984}+4=0\)
Tìm x biết \(\frac{45-x}{1963}+\frac{40-x}{1968}+\frac{35-x}{1973}+\frac{30-x}{1978}+4=0\)
