\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}-\frac{x+1}{13}+\frac{x+1}{14}=0\)
\(\left(x+1\right).\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)=0\)
vì \(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\)\(\ne\)0 nên x + 1 = 0 \(\Rightarrow\)x = -1
tim x biet
a.\(\frac{x+1}{10}+\frac{x+1}{11}=\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
b.\(\frac{x+4}{1990}+\frac{x+3}{1991}=\frac{x+2}{1992}+\frac{x+1}{1993}\)
tim x biet :\(\frac{x+1}{10}+\frac{x+1}{11}=\frac{x+1}{12}+\frac{x+1}{13}\)
Tim x:
\(\frac{x+1}{10}\)\(+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
Tim x biet \(\frac{x+1}{10}\)+\(\frac{x+1}{11}\)+\(\frac{x+1}{12}\)= \(\frac{x+1}{13}\)+\(\frac{x+1}{14}\)
\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
a,\(x+\frac{1}{10}+x+\frac{1}{11}+x+\frac{1}{12}=x+\frac{1}{13}+x+\frac{1}{14}\)
\(\frac{x+4}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
Tìm x:
\(\frac{X+1}{10}+\frac{X+1}{11}+\frac{X+1}{12}=\frac{X+1}{13}+\frac{X+1}{14}\)
Tìm x , biết : \(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
