\(\frac{X-28-124}{2011}+\frac{X-124-2011}{28}+\frac{X-2011-28}{124}=3\)
tìm x"
\(\frac{x-28-124}{2011}+\frac{x-124-2011}{28}+\frac{x-2011-28}{124}=3\)
giúp mình nha m.n
\(\frac{x-28-124}{2011}+\frac{x-124-2011}{28}+\frac{x-2011-28}{124}\)=3
Tìm số hữu tỉ x, biết:
a, \(\frac{x-100}{24}+\frac{x-98}{26}+\frac{x-96}{28}=3\)3
b, \(\frac{x-1}{65}+\frac{x-3}{63}=\frac{x-5}{61}+\frac{x-7}{59}\)
c, \(\frac{x-28-124}{2011}+\frac{x-124-2011}{28}+\frac{x-2011-28}{124}=3\)
giúp với gấp lắm
Tìm các số tự nhiên x, y biết :
a) 2x = 4y - 1 và 27y = 3x + 8
b) \(\frac{x-28-124}{2011}+\frac{x-124-2011}{28}+\frac{x-2011-28}{124}\)
tìm x biết:
\(\frac{x-28-124}{2011}+\frac{x-24-2011}{28}+\frac{x-2011-28}{124}=3\)
\(\left(4x-1\right)^2=\left(1-4x\right)^4\)
\(\frac{x-28-124}{2011}\)\(+\frac{x-124-2011}{28}\)\(+\frac{x-2011-28}{124}\)\(=3\)
x-28-124\2011+x-124-2011\28+x-2011-28\124=3
x-28-124/2011+x-124-2011/28+x-2011-28/124=3