\(\frac{x-2}{4}=\frac{-16}{2-x}\)
\(\Leftrightarrow\frac{x-2}{4}=\frac{16}{x-2}\)
\(\Leftrightarrow\left(x-2\right)^2=64\)
\(\Leftrightarrow\orbr{\begin{cases}x-2=8\\x-2=-8\end{cases}\Leftrightarrow\orbr{\begin{cases}x=10\\x=-6\end{cases}}}\)
Vậy x=10; x=-6
\(\frac{x-2}{4}=\frac{-16}{2-x}\)
\(\Leftrightarrow\frac{x-2}{4}=\frac{16}{x-2}\)
\(\Leftrightarrow\left(x-2\right)^2=64\)
\(\Leftrightarrow\orbr{\begin{cases}x-2=8\\x-2=-8\end{cases}\Leftrightarrow\orbr{\begin{cases}x=10\\x=-6\end{cases}}}\)
Vậy x=10; x=-6
\(\frac{x-2}{4}=\frac{-16}{2-x}\)
\(\frac{x-2}{4}=\frac{16}{x-2}\)
\(\left(x-2\right)^2=16.4\)
\(\left(x-2\right)^2=64\)
\(x-2=8\)
\(x=10\)
\(\frac{x-2}{4}=-\frac{16}{2-x}\)
\(\Rightarrow\left(x-2\right).\left(2-x\right)=4.\left(-16\right)\)
\(\left(x-2\right).\left(2-x\right)=-64\)
\(\Rightarrow\hept{\begin{cases}x-2=-64\\2-x=-64\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x=-64+2=-62\\x=2-\left(-64\right)=66\end{cases}}\)
