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28 tháng 9 2020 lúc 22:44
\(\frac{x+1}{2014}+\frac{x+2}{2013}+\frac{x+3}{2012}+\frac{x+10}{2005}+\frac{x+11}{2004}+\frac{x+12}{2003}\)
Tìm x biết:
a)(x-5)x+2014-(x-5)x+2015
b)\(\frac{x-1}{2014}+\frac{x-2}{2013}+\frac{x-3}{2012}=\frac{x-10}{2005}+\frac{x-11}{2004}+\frac{x-12}{2003}\)
Tìm x: a, \(\frac{x-2004}{2003}+\frac{x-2003}{2004}+\frac{x-2005}{2004}=3+\frac{2005}{2003}\)\(+\frac{2004}{2005}\)
\(\frac{x+6}{2001}+\frac{x+5}{2002}+\frac{x+4}{2003}=\frac{x+3}{2004}+\frac{x+2}{2005}\)+\(\frac{x+1}{2006}\)
Tìm x
tìm x biết :\(\frac{x-1}{2005}+\frac{x-2}{2004}-\frac{x-3}{2003}=\frac{x-4}{2002}\) Giúp mình với
Tìm x biết : \(\frac{x+5}{2005}+\frac{x+6}{2004}+\frac{x+7}{2003}=-3\)
\(\frac{x+2005}{2004}\)-\(\frac{x+2005}{2001}\)= \(\frac{x+2005}{2002}\)-\(\frac{x+2005}{2003}\)
hộ mình đi mấy bạn
tìm x
\(\frac{x+5}{2005}+\frac{x+6}{2004}+\frac{x+7}{2003}=-3\)
\(\frac{x+1}{1974}+\frac{x+2}{1973}+\frac{x+3}{1972}=-3\)
\(\frac{x+5}{2005}+\frac{x+6}{2004}+\frac{x+7}{2003}=-3\)
TÌM X