Question

Tìm x biết

\(\frac{x-1}{x+2}=\frac{x-2}{x+3}\)

Answer 1

Quy đồng MTC ( x + 2 )(x+ 3 ) 

=> cùng mẫu bằng nhau khi tử  bằng nhau 

=> ( x - 1 )(x+3 ) = ( x - 2 )(x+ 2 )

=> x^2 + 3x - x - 3 = x^2 - 2x + 2x - 4 

=> x^2 + 2x - 3 = x^2 - 4 

=> 2x = -4 + 3 

=> 2x = -1 

=> x = -1/2 

Answer 2

=> \(\left(x-1\right)\left(x+3\right)=\left(x-2\right)\left(x+2\right)=>x^2-x+3x-3=x^2-2x+2x+4=>x^2+2x-3=x^2+4=>2x=4+3=>2x=7=>x=3.5\)