x−17/1990+x−21/1986+x+1 1004=4⇔x−17/1990−1+x−21/1986−1+x+1/1004−2=0
⇔x−2007/1990+x−2007/1986+x−2007/1004=0
⇔(x−2007)(1/1990+1/1986+1/1004)=0
⇔x−2007=0⇔x=2007
x−17/1990+x−21/1986+x+1 1004=4⇔x−17/1990−1+x−21/1986−1+x+1/1004−2=0
⇔x−2007/1990+x−2007/1986+x−2007/1004=0
⇔(x−2007)(1/1990+1/1986+1/1004)=0
⇔x−2007=0⇔x=2007
\(\frac{59-x}{41}+\frac{57-x}{43}+\frac{55-x}{45}+\frac{53-x}{47}+\frac{51-x}{49}=-5\) tìm x
\(\frac{x-5}{1990}+\frac{x-15}{1980}+\frac{x-25}{1970}=\frac{x-1990}{5}+\frac{x-1980}{15}+\frac{x-1970}{25}\) tìm x
\(\frac{x+14}{86}+\frac{x+15}{85}+\frac{x+16}{84}+\frac{x+17}{83}+\frac{x+116}{4}=0\) tìm x
Tìm x,biết:
a)\(\frac{x+1}{999}+\frac{x+2}{998}=\frac{x+3}{997}+\frac{x+4}{996}\)
b)\(\frac{x+1}{1001}+\frac{x+2}{1002}=\frac{x+3}{1003}+\frac{x+4}{1004}\)
c)\(|x|-\frac{15}{2}=\frac{15}{4}\)
d)\(|\frac{3}{4}-x|+1|=\frac{3}{2}\)
1, tìm x
\(5\frac{2}{3}x+1\frac{2}{3}=4\frac{1}{2}\)
\(\frac{x}{27}=\frac{-2}{9}\)
|x+1,5|=2
2, tìm GTLN của biểu thức A=|x-1004|-|x+1003|
tìm x biết
\(\frac{x-17}{33}+\frac{x-21}{29}+\frac{x}{25}=4\)
Tìm các số x,y,z biêt : \(\frac{40}{x-30}=\frac{20}{y-15}=\frac{28}{z-21}\)và xyz= 22400
Tìm tập hợp các số nguyên x biết:
\(a,4\frac{5}{9}:2\frac{5}{8}-7< x< \left(3\frac{1}{5}:3,2+4,5.1\frac{31}{45}\right):\left(-21\frac{1}{2}\right)\)
\(b,\frac{-17}{21}:\left(\frac{5}{4}-\frac{2}{5}\right)< x+\frac{4}{7}< 1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}\)
Giúp mik nha! Ai làm đc mik cho 3 tick!
tìm x,biết:
a)\(\frac{2}{\left(x+2\right)\left(x+4\right)}+\frac{4}{\left(x+4\right)\left(x+8\right)}+\frac{6}{\left(x+8\right)\left(x+14\right)}=\frac{x}{\left(x+2\right)\left(x+14\right)}\)
b)\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
c)\(\left(x+2\right)^2=\frac{38}{25}+\frac{9}{10}-\frac{11}{15}+\frac{13}{21}-\frac{15}{28}+\frac{17}{36}-...+\frac{197}{4851}-\frac{199}{4950}\)
giúp tớ với,huhu
Biêt x, y , z thoả mãn: \(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\)và x - 2y + 3z = 10. Tìm x,y,z.
Tìm x
\(\frac{x-241}{17}-\frac{x-220}{19}+\frac{x-195}{21}+\frac{x-166}{23}=10\)