Question

tìm x biết

\(\frac{2x}{3}=\frac{7x-3}{15}\)

\(\frac{11x-2}{7x+5}=\frac{11}{8}\)

\(\frac{2x+3}{3x+1}=\frac{3}{4}\)

giup mk mk se tk 

Answer 1

\(\frac{2x}{3}=\frac{7x-3}{15}\)

\(\Rightarrow30x=3\left(7x-3\right)\)

\(30x=21x-9\)

\(9x=-9\)

\(x=-1\)

\(\frac{11x-2}{7x+5}=\frac{11}{8}\)

\(\Rightarrow8\left(11x-2\right)=11\left(7x+5\right)\)

\(88x-16=77x+55\)

\(11x=71\)

\(x=\frac{71}{11}\)

\(\frac{2x+3}{3x+1}=\frac{3}{4}\)

\(\Rightarrow4\left(2x+3\right)=3\left(3x+1\right)\)

\(8x+12=9x+3\)

\(-x=-9\)

\(x=9\)

Answer 2

mk lộn đề câu a

bn giải lại giùm mk nha

\(\frac{2x+3}{6}=\frac{7x-3}{15}\)